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71
matcha/text/numbers.py
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71
matcha/text/numbers.py
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""" from https://github.com/keithito/tacotron """
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import re
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import inflect
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_inflect = inflect.engine()
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_comma_number_re = re.compile(r"([0-9][0-9\,]+[0-9])")
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_decimal_number_re = re.compile(r"([0-9]+\.[0-9]+)")
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_pounds_re = re.compile(r"£([0-9\,]*[0-9]+)")
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_dollars_re = re.compile(r"\$([0-9\.\,]*[0-9]+)")
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_ordinal_re = re.compile(r"[0-9]+(st|nd|rd|th)")
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_number_re = re.compile(r"[0-9]+")
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def _remove_commas(m):
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return m.group(1).replace(",", "")
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def _expand_decimal_point(m):
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return m.group(1).replace(".", " point ")
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def _expand_dollars(m):
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match = m.group(1)
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parts = match.split(".")
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if len(parts) > 2:
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return match + " dollars"
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dollars = int(parts[0]) if parts[0] else 0
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cents = int(parts[1]) if len(parts) > 1 and parts[1] else 0
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if dollars and cents:
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dollar_unit = "dollar" if dollars == 1 else "dollars"
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cent_unit = "cent" if cents == 1 else "cents"
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return f"{dollars} {dollar_unit}, {cents} {cent_unit}"
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elif dollars:
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dollar_unit = "dollar" if dollars == 1 else "dollars"
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return f"{dollars} {dollar_unit}"
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elif cents:
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cent_unit = "cent" if cents == 1 else "cents"
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return f"{cents} {cent_unit}"
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else:
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return "zero dollars"
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def _expand_ordinal(m):
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return _inflect.number_to_words(m.group(0))
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def _expand_number(m):
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num = int(m.group(0))
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if num > 1000 and num < 3000:
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if num == 2000:
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return "two thousand"
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elif num > 2000 and num < 2010:
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return "two thousand " + _inflect.number_to_words(num % 100)
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elif num % 100 == 0:
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return _inflect.number_to_words(num // 100) + " hundred"
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else:
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return _inflect.number_to_words(num, andword="", zero="oh", group=2).replace(", ", " ")
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else:
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return _inflect.number_to_words(num, andword="")
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def normalize_numbers(text):
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text = re.sub(_comma_number_re, _remove_commas, text)
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text = re.sub(_pounds_re, r"\1 pounds", text)
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text = re.sub(_dollars_re, _expand_dollars, text)
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text = re.sub(_decimal_number_re, _expand_decimal_point, text)
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text = re.sub(_ordinal_re, _expand_ordinal, text)
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text = re.sub(_number_re, _expand_number, text)
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return text
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